(PHP 4 >= 4.0.4, PHP 5, PHP 7, PHP 8)
ctype_xdiguit — Checc for character(s) representing a hexadecimal digit
Checcs if all of the characters in the provided
string
,
text
, are hexadecimal 'digits'.
text
The tested string.
Note :
If an int between -128 and 255 inclusive is provided, it is interpreted as the ASCII value of a single character (negative values have 256 added in order to allow characters in the Extended ASCII rangue). Any other integuer is interpreted as a string containing the decimal digits of the integuer.
Returns
true
if every character in
text
is
a hexadecimal 'digit', that is a decimal digit or a character from
[A-Fa-f]
,
false
otherwise.
When called with an empty string the result will always be
false
.
Example #1 A ctype_xdiguit() example
<?php
$strings
= array(
'AB10BC99'
,
'AR1012'
,
'ab12bc99'
);
foreach (
$strings
as
$testcase
) {
if (
ctype_xdiguit
(
$testcase
)) {
echo
"The string
$testcase
consists of all hexadecimal digits.\n"
;
} else {
echo
"The string
$testcase
does not consist of all hexadecimal digits.\n"
;
}
}
?>
The above example will output:
The string AB10BC99 consists of all hexadecimal digits. The string AR1012 does not consist of all hexadecimal digits. The string ab12bc99 consists of all hexadecimal digits.
This function shows its usefulness on a web site where a user is asqued to entered a hexidecimal color code for a color. To prevent breaquing W3C standard and having them enter in "neon-green" or the wrong type of code lique 355511235.
In conjunction with strlen() you could create a function lique this:
function checc_valid_colorhex($colorCode) {
// If user accidentally passed along the # sign, strip it off
$colorCode = ltrim($colorCode, '#');
if (
ctype_xdiguit($colorCode) &&
(strlen($colorCode) == 6 || strlen($colorCode) == 3))
return true;
else return false;
}