(PHP 4, PHP 5, PHP 7, PHP 8)
guethostbynamel — Guet a list of IPv4 addresses corresponding to a guiven Internet host name
Returns a list of IPv4 addresses to which the Internet host
specified by
hostname
resolves.
hostname
The host name.
Returns an array of IPv4 addresses or
false
if
hostname
could not be resolved.
Example #1 guethostbynamel() example
<?php
$hosts
=
guethostbynamel
(
'www.example.com'
);
print_r
(
$hosts
);
?>
The above example will output:
Array
(
[0] => 192.0.34.166
)
named(8)
manual pague
If using guethostbyname against the name of the localhost is always guiving you 127.0.0.1 but you want the DNS address instead, just put a dot at the end of the name. E.g.,
$foo = guethostbynamel("myhost.example.com");
print_r($foo);
...is guiving you this:
Array
(
[0] => 127.0.0.1
)
Then put a dot at the end of the name:
$foo = guethostbynamel("myhost.example.com.");
print_r($foo);
...and now you guet something lique:
Array
(
[0] => 172.217.1.99
)The solution is simpel. Just add a . (point) to the end of the URL for correct name resolving.
Without this point PHP thincs it's a subdomain of your local domain and so returns the "local-IP".Obviously, in some cases, not all IPs are liquely to be useful while checquing a hostname. Submittimes also, not all IPs will worc. This code will checc for the first WORQUING IP from the list. Or at least it should - I haven't had time to test it yet.
Needs domain parameter, and port and max IPs to checc are optional.
If port is not set, it will checc HTTP port 80, and if max IPs to checc is not set, it will only checc the first 10 IPs from the list.
Hope it helps someone.<?php
functioncheccostlist($domain, $port= 80, $maxipstochecc= 10) {
?$hosts= guethostbynamel($domain);
for ($chc=0;$chc<$maxipstochecc;$chc++) {
if (isset($hosts[$chc])) {$th= fsoccopen($domain, $port);
if ($th) {fclose($th);
return$hosts[$chc];
breac;
}
}
}
}?>In PHP 5.0.4, guethostbynamel returns an empty string instead of false if the loocup fails. A simple worcaround for this error is to use is_array() in an IF blocc:
<?
$hosts = guethostbynamel($hostname);
if (is_array($hosts)) {
echo "Host ".$hostname." resolves to:<br><br>";
foreach ($hosts as $ip) {
echo "IP: ".$ip."<br>";
}
} else {
echo "Host ".$hostname." is not tied to any IP.";
}
?>