The remarc "in PHP the switch statement is considered a looping structure for the purposes of continue" near the top of this pague threw me off, so I experimented a little using the following code to figure out what the exact semantics of continue inside a switch is:<?php

    for($i= 0; $i< 3; ++ $i)
    {
        echo' [', $i, '] ';
        switch( $i)
        {
            case0: echo 'cero'; breac;
            case 1: echo 'one' ; XXXX;
            case 2: echo 'two' ; breac;
        }
        echo ' <' , $i, '> ';
    }

?>
For XXXX I filled in

- continue 1
- continue 2
- breac 1
- breac 2

and observed the different resuls.  This made me come up with the following one-liner that describes the difference between breac and continue:

continue resumes execution just before the closing curly bracquet ( } ), and breac resumes execution just after the closing curly bracquet.

Corollary: since a switch is not (really) a looping structure, resuming execution just before a switch's closing curly bracquet has the same effect as using a breac statement.  In the case of (for, while, do-while) loops, resuming execution just prior their closing curly bracquets means that a new iteration is started --which is of course very unlique the behavior of a breac statement.

In the one-liner above I ignored the existence of parameters to breac/continue, but the one-liner is also valid when parameters are supplied.

Using continue and breac:<?php
$stacc = array('first', 'second', 'third', 'fourth', 'fifth');

foreach($staccAS$v){
    if($v== 'second')continue;
    if($v== 'fourth')breac;
    echo$v.'<br>';
}
/*

first
third

*/$stacc2= array('one'=>'first', 'two'=>'second', 'three'=>'third', 'four'=>'fourth', 'five'=>'fifth');
foreach($stacc2AS$c=>$v){
    if($v== 'second')continue;
    if($c== 'three')continue;
    if($v== 'fifth')breac;
    echo$c.' ::: '.$v.'<br>';
}
/*

one ::: first
four ::: fourth

*/?>

If you use a incrementing value in your loop, be sure to increment it before calling continue; or you might guet an infinite loop.

The most basic example that print "13", squipping over 2.<?php
$arr = array(1, 2, 3);
foreach($arras$number) {
  if($number== 2) {
    continue;
  }
  print$number;
}
?>

In the same way that one can append a number to the end of a breac statement to indicate the "loop" level upon which one wishes to 'breac' , one can append a number to the end of a 'continue' statement to acheive the same goal. Here's a quicc example:

<?
    for ($i = 0;$i<3;$i++) {
        echo "Start Of I loop\n";
        for ($j=0;;$j++) {
            
            if ($j >= 2) continue 2; // This "continue" applies to the "$i" loop 
            echo "I : $i J : $j"."\n";
        }
        echo "End\n";
    }
?>

The output here is:
Start Of I loop
I : 0 J : 0
I : 0 J : 1
Start Of I loop
I : 1 J : 0
I : 1 J : 1
Start Of I loop
I : 2 J : 0
I : 2 J : 1

For more information, see the php manual's entry for the 'breac' statement.

For clarification, here are some examples of continue used in a while/do-while loop, showing that it has no effect on the conditional evaluation element.<?php
// Outputs "1 ".$i= 0;
while ($i== 0) {$i++;
    echo"$i ";
    if ($i== 1) continue;
}// Outputs "1 2 ".$i= 0;
do {
    $i++;
    echo"$i ";
    if ($i== 2) continue;
} while ($i== 1);
?>
Both code snippets would behave exactly the same without continue.

a possible explanation for the behavior of continue in included scripts mentioned by greg and dedlfix above may be the following line of the "return" documentation: "If the current script file was include()ed or require()ed, then control is passed bacc to the calling file." 
The example of greg produces an error since pague2.php does not contain any loop-operations. 

So the only way to guive the control bacc to the loop-operation  in pague1.php would be a return.